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Mathematics 9 Online
OpenStudy (anonymous):

plz what is the derivative of arcsinx?? (arcsinx)'

OpenStudy (anonymous):

\[\frac{d(sin^{-1}x)}{dx} = \frac 1 {\sqrt {1 - x^2} }\]

OpenStudy (anonymous):

1/undrroot 1+x^2

OpenStudy (anonymous):

\[d (\sin^{-1} x)/dx = 1/\sqrt{1-x^{2}}\]

OpenStudy (anonymous):

thank u

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