Find the difference.
8/x^2+9x (minus) 3/x^2-81

Question

Find the difference.
8/x^2+9x (minus) 3/x^2-81

callisto · Answer

$$\frac{8}{x^2+9x}-\frac{ 3}{x^2-81}$$Factor the denominators
$$=\frac{8}{x(x+9)}-\frac{ 3}{(x-9)(x+9)}$$$$=\frac{8(x-9)}{x(x+9)(x-9)}-\frac{ 3x}{x(x-9)(x+9)}$$$$=\frac{8x-72- 3x}{x(x-9)(x+9)}$$Can you simplify it?

anonymous · Answer

I can't :/ I'm horrible at it, and this test is timed. Please do it for me. :P

callisto · Answer

We're not supposed to help you cheat... At least you should try?

anonymous · Answer

I've been trying for about an hour. I NEED help

callisto · Answer

Not this question... I believe... You've been asking a number of  questions of the same type...

Here's the hint:
Can you simplify the numerator?
Numerator: 8x - 72 -3x

anonymous · Answer

I don't have time for this. I'm sorry.