Question

Find the difference.
8/x^2+9x (minus) 3/x^2-81

Answer 1

\[\frac{8}{x^2+9x}-\frac{ 3}{x^2-81}\]Factor the denominators
\[=\frac{8}{x(x+9)}-\frac{ 3}{(x-9)(x+9)}\]\[=\frac{8(x-9)}{x(x+9)(x-9)}-\frac{ 3x}{x(x-9)(x+9)}\]\[=\frac{8x-72- 3x}{x(x-9)(x+9)}\]Can you simplify it?

Answer 2

I can't :/ I'm horrible at it, and this test is timed. Please do it for me. :P

Answer 3

We're not supposed to help you cheat... At least you should try?

Answer 4

I've been trying for about an hour. I NEED help

Answer 5

Not this question... I believe... You've been asking a number of questions of the same type...

Here's the hint:
Can you simplify the numerator?
Numerator: 8x - 72 -3x

Answer 6

I don't have time for this. I'm sorry.