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Simplify: (b3 – 11) – (12b + 4) -11b4 – 15 b3 – 12b – 7 -11b4 – 7 b3 – 12b – 15
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=b3-11-12b-4 =b3-12b-15
So last one is correct:)
Find the perimeter of a rectangle with length 5b – 4 and width 4a2 20a2b + 16a2 20a2b – 16a2 4a2 + 5b – 4 8a2 + 10b – 8
Perimeter of a rect.=2(l+b)
2(5b-4+4a2)
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=10b-8+8a2
Clear???
yea thanks :)
yw:)
In which class do u study?
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@ladynisha
?????????
Not want to tell no problem:) It's ur wish.
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