Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 4x - ___

Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of 
(– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 4x - ___

campbell_st · Answer

if it has intercepts at x = -6 and x = 2 and a vertex at (-2, -16) the parabola is concave  up.

then the equation is 

y= (x +6)(x -2)

expanding gives

y = x^2 + 4x - 12

campbell_st · Answer

the missing value is 12