2x^2-x=-1
use the quadratic formula to solve the equation
solution set is?

Question

2x^2-x=-1
use the quadratic formula to solve the equation
solution set is?

campbell_st · Answer

rewrite the equation

$$2x^2 -x + 1 = 0$$

you have  a = 2, b = -1 and c = 1

then substitute the values into the equation

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

which gives

$$x = \frac{1 \pm \sqrt{1^2 - 4\times2\times1}}{2\times2}$$

just simplify it for your answer

campbell_st · Answer

Ohh, I forgot...you will have a complex number in the solution

anonymous · Answer

1/4(1-i{sqrt}7)?

anonymous · Answer

$$1/4(1-i \sqrt{7})$$

campbell_st · Answer

thats 1 solution 

the solutions are 

$$x = \frac{1 +i \sqrt{7}}{4}.... and ....x = \frac{1 - i \sqrt{7}}{4}$$