Question

2x^2-x=-1
use the quadratic formula to solve the equation
solution set is?

Answer 1

rewrite the equation

\[2x^2 -x + 1 = 0\]

you have a = 2, b = -1 and c = 1

then substitute the values into the equation

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

which gives

\[x = \frac{1 \pm \sqrt{1^2 - 4\times2\times1}}{2\times2}\]

just simplify it for your answer

Answer 2

Ohh, I forgot...you will have a complex number in the solution

Answer 3

1/4(1-i{sqrt}7)?

Answer 4

\[1/4(1-i \sqrt{7})\]

Answer 5

thats 1 solution

the solutions are

\[x = \frac{1 +i \sqrt{7}}{4}.... and ....x = \frac{1 - i \sqrt{7}}{4}\]