Question

Simplify. State any restrictions on the variables.

Answer 1

\[{6a^2+9a} \over {12a^2}\]

Answer 2

firstly.... the restriction is a cannot equal zero

next factor the numerator

\[\frac{3a(2a + 3)}{12a^2}\]

cancel the common factor of 3a

leaves

\[\frac{2a +3}{4a}\]

Answer 3

Restrictions?

Answer 4

@campbell_st Restrictions?

Answer 5

@campbell_st Nvm. Didn't notice what you mentioned in previous post >.<.

Answer 6

the restiction is stated in the 1st sentence a cannot equal zero