Question

2^x^2=32(2^4x)

Answer 1

\[2^{x^2}=32(2^{4x})\]
\[2^{x^2}=2^{5(2^{4x})}\]
\[x^2=5(2^{4x})\]

Answer 2

and then :) use the log ?

Answer 3

wait typo there

Answer 4

ohhhhhhhh

Answer 5

\[2^{x^2}=32(2^{4x})\]
\[2^{x^2}=2^{5}{(2^{4x})}\]
\[2^{x^2}=2^{5+4x}\]
\[x^2=5+4x\]
solve

Answer 6

lol.. so easy :)) but I can't do it :) thanks a lot <3<3

Answer 7

yw

Answer 8

2x . 3^x= 7x . 5^x