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solve 16x^2-8x-3=0
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Do you know how to factor?
16x^2-8x-3=0 (4x-3)(4x+1) =0 (4x-3)=0 or (4x+1) =0 Can you solve x?
*additional steps: 16x^2-8x-3=0 16x^2 - 12x + 4x -3 =0 4x(4x - 3) + 4x-3 =0 (4x-3)(4x+1) = 0
\[\LARGE{\color{red}{x=\frac{3}{4} or \frac{-1}{4}}}\]
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