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Mathematics 8 Online
OpenStudy (anonymous):

x-2 3 = - x+3 4

OpenStudy (anonymous):

\[\frac{x-2}{x+3}=\frac{3}{4}\]\[4{(x-2)}={3}{(x+3)}\]Can you solve it now?

OpenStudy (anonymous):

*technique used here : cross multiplication

OpenStudy (anonymous):

can u do step by step work shown please

OpenStudy (anonymous):

Perhaps... slow motion... \[\frac{x-2}{x+3}=\frac{3}{4}\] Multiply both sides by (x+3), what do you get?

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