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OpenStudy (anonymous):
simplify by removing factors of 1 n^2-1/(n+1)^2
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OpenStudy (anonymous):
\[\frac{n^2-1}{(n+1)^2}=\frac{(n-1)(n+1)}{(n+1)^2}\]Cancel the common factor, what do you get?
OpenStudy (anonymous):
|dw:1339561141738:dw|
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