Question

a-3a+c+4a-2b+6-a+b-5c

Answer 1

Combine like terms.

Answer 2

If \(ac+bc\), then \((a+b)c\).

Answer 3

i know but idont knoq how to add those 2 a's

Answer 4

add/subtract "LIKE" terms only

-2a + c + 4a - 2b + 6 + a + b - 5c
2a + c - 2b + 6 + a + b - 5c
3a + c - 2b + 6 + b - 5c
3a -4c -b + 6

Answer 5

You have \(a-3a+4a-a\). That is the same as \(1a-3a+4a-1a\). So: \((1-3+4-1)a\).

Answer 6

\[a-3a+c+4a-2b+6-a+b-5c\]\[=(a-3a)+(c)+(4a)+(-2b)+6+(-a)+b+(-5c)\]\[=(a-3a+4a-a)+(-2b+b)+(c-5c)+6\]\[=(1-3+4-1)a+(-2+1)b+(1-5)c+6\]