Question

y varies jointly with x and the square of n. When y = 25, x = 3 and n = 4. Find the value of y when x = 5 and n = 10. Round to the nearest whole number.

Answer 1

\[y=kxn^2\]

Answer 2

its 260

Answer 3

y / (xn^2) = k
25 / (3•16) = 25/48 = k

y / (5•100) = 25/48
y = 500 • 25/48
y = about 260

Answer 4

So what is your question then?

Answer 5

I didnt know it at first then I tried it