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OpenStudy (anonymous):

If I have an Ion, for example Na2+, how high is the lost charge? My idea would be to simply say 2*(1,602*10^-19).

OpenStudy (anonymous):

correct. So what's your ques?

OpenStudy (anonymous):

yes then what you need? Is two electrons are lost due quantization of charge; charge will be + 2*(1,602*10^-19).

OpenStudy (anonymous):

u hv a good idea!

OpenStudy (anonymous):

My question was, if I`m right with my idea :D

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