Question

If you are using the unit Kelvin, you are measuring the average

Answer 1

you are measuring from absolute zero, but i don't know which average they are talking about.

Answer 2

Probably what's wanted is "average kinetic energy per particle," since the equipartition theorem guarantees that at equilibrium the average kinetic energy per degree of freedom equals kT, where k is Boltzmann's constant and T is the absolute temperature.

Answer 3

Temerature
\[T~\left[\text K \right]\]