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an=a1+(n-1)*d. what is the 1000 term. 24,31,38,45,52,....
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Okay first term 'a1' is '24', and the common difference 'd', i.e. the difference between any 2 consecutive terms, and 'n' = 1000, since you need the 1000th term So, substitute the values of 'a', 'd' and 'n' in the equation you've stated, and find out \(a_n\).
@apoorvk so itd be 24+(1000-1)*7?
@apoorvk
yes! right-o!
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