Solve 20x2 + 70x + 20 = 0.
Answer
x equals the quantity of 70 plus or minus the square root of 33 all over 4
x equals the quantity of negative 70 plus or minus the square root of 33 all over 4
x equals the quantity of negative 7 plus or minus the square root of 33 all over 4
x equals the quantity of 7 plus or minus the square root of 6 all over 4
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OpenStudy (anonymous):
20x^2 + 70x + 20 = 0
10(2x^2 + 7x + 2) = 0
\[x = \frac{-b ± \sqrt{b^{2} - 4ac}}{2a}\] where a = 2, b = 7, and c = 2
OpenStudy (anonymous):
Okay, then solve?
OpenStudy (anonymous):
I'm not so good at that part
OpenStudy (anonymous):
Yes. Plug in the values and that should lead you to the answer.
OpenStudy (anonymous):
\[x = \frac{-7 ± \sqrt{7^{2} - 4(2)(2)}}{2(2)}\]
Can you simplify and tell me what you get?
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OpenStudy (anonymous):
Yes, one sec.
OpenStudy (anonymous):
\[-7 \pm \sqrt{33} \div 4\]
OpenStudy (anonymous):
well over 4
OpenStudy (anonymous):
?
OpenStudy (anonymous):
Yup. Make sure that the 4 is under all of -7 ± √33
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OpenStudy (anonymous):
This such equal answer # 3
OpenStudy (anonymous):
Yup.
OpenStudy (anonymous):
Yes, I just couldn't figure out how to do that . lol
Thank you