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OpenStudy (anonymous):
What is the area of a sector with radius 10" and measure of arc equal to 45°?
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OpenStudy (dumbcow):
take area of circle times ratio of 45/360
ganeshie8 (ganeshie8):
(45/360) x pi x r x r
OpenStudy (anonymous):
would it be 7.85? or no
OpenStudy (unklerhaukus):
\[A_{\text{circle}}=\pi\times r^2\] \[A_{\text{sector}}=\frac{\theta°}{360°}\times\pi\times r^2\]
OpenStudy (unklerhaukus):
In this example \[r=10\text{ in}\]\[\theta°=45°\]
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OpenStudy (unklerhaukus):
7.85 is not correct
OpenStudy (anonymous):
haha i accidentally put a 2piR instead of piR^2 I got 39.25 is that correct?
OpenStudy (unklerhaukus):
yes yes
OpenStudy (anonymous):
ah!! haha YES!! haha success
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