Question

Solve by completing the square:

-3x^2-6x-5=0

Answer 1

I seem to have gone wrong somewhere in my working I checked my answer on wolframalpha but it is a little off...

Answer 2

Can you post your work so we can have a look at it to see where you went wrong?

Answer 3

\[-3x^2-6x-5=0\]
solve this with quadratic equation :

\[-b \pm \sqrt{b^2-4ac}/2a\]

Answer 4

wait i am posting the image

Answer 5

I see the mistake I made now but it's still not the same answer I got
\[x=1 \pm \frac{2}{3}i\]

Answer 6

-3x^2-6x-5=0

-3x^2-6x=5

-3(x^2+2x)=5

-3(x^2+2x+1-1)=5

-3((x^2+2x+1)-1)=5

-3((x+1)^2-1)=5

-3(x+1)^2-3(-1)=5

-3(x+1)^2+3=5

-3(x+1)^2+3-5=0

-3(x+1)^2-2=0

Answer 7

I'll let you take it from here

Answer 8

I see where I went wrong. Thanks everyone!!!