Question

Solve 2x^2 = -10x.
A:x = 2, x = -5
B:x = 2, x = 5
C:x = 0, x = 5
D:x = 0, x = -5

Answer 1

put 10x on the left side first

\[2x^2 + 10x = 0\]

now facotr!

\[2x(x + 10) = 0\]

now equate each factor to zero and solve for x


solve for x when

2x = 0

solve for x when

x + 10 = 0

Answer 2

do you get it?

Answer 3

\[2x^2=-10x\]
\[2x^2/(-10)=x\]
\[-x^2/5=x\]
\[-x^2=5x\]
\[-x^2/x=5\]
\[-x=5\]
\[x=-5\]

Answer 4

careful here...you shouldn't divide by x because you will be missing one factor ;)