Question

m^2/n^2is equivalent to _____.

a) mn^-2
b) m^-2n^-2
c) m^2n^-2
d) m^-2n^2

Answer 1

hint!!! \[\LARGE \frac{1}{a^n} = a^{-n}\]
hope that helps :)

Answer 2

yes, but this equals the denominator, so what is the numerator? :S

Answer 3

the numerator stays the same ;)

Answer 4

but if you wanna know.. \[\LARGE \frac{1}{b^{-n}} = b^n\]

Answer 5

C is the correct anwer..

Answer 6

As:
\[1/b^2 = b^{-2}\] therefore,

\[m^2/n^2 = \]\[m^2 \times 1/n^2 = m^2 \times n^{-2}\]