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find the area of the trapezoid with height of 8m and base 14m and 19m
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\[\large Area = \frac{h(b_1 + b_2)}{2}\]
does that help?
h = height \(b_1\) and \(b_2\) are the bases
.5 (14+19) = .5(33) =* 16.5 m*
careful..don;t forget to multiply by the height ;)
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yes but I don't know where i keep messing up at
substitute the values \[Area = \frac{8(14 + 19)}{2}\] you can divide 8 by 2 right there \[Area = 4(14 + 19)\]\[Area = 4(33)\]
16.5 m * 8 = 132m
now just multiply 4 x 33 and you have your answer ^_^
ok I was multiplying the wrong number which was 19 instead of addding thanks
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