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In the below system, solve for y in the first equation. x – 3y = –6 2x – 7y = 10 a. x + 2 b.x + 6 c.–x + 2 d. x + 2
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Substitution method?
yes
this is confusing to me because it says to solve for y for x – 3y = –6 If you do this you get x – 3y = –6 x +6 = 3y \[y=\frac{x}{3}+2\]
im sorry these are the answers 2x + y = 11 5x – 2y = –1 a. 2x + 11 b.–2x + 11 c. 2x – 11 d.–2x – 11
2x + y = 11 2x -2x + y = 11 -2x
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