Question

http://media01.switchedononline.com/g_alg01_2011/10/353.gif

Answer 1

\[\color{red}{\frac{2y+a}{2y+b}=\frac{a}{b}.}\]\[2yb+ab=2ya+ab\]\[2y(b-a)=0=>\color{purple}{y=0.}\]

Answer 2

now I will not solve any question further.
It is upto u to try & get the answers now^_^

Answer 3

k

Answer 4

First cross multiply. Then u get
b(2y+a)=a(2y+b)
2by+ab=2ay+ab
2by-2ay+ab-ab=0
2by-2ay=0
2y(b-a)=0
y=0 or b-a=0
b=a

Answer 5

ya sorry I forget to write one statement.
good work @ajprincess.

Answer 6

This one is good:)
\[\LARGE{\color{green}{b-a=0\implies b=a.}}\]

Answer 7

Ya it's really gud.:)

Answer 8

thanx:)

Answer 9

u r welcome.:)

Answer 10

@ Aj how come its either y=0 or b-a=0
The option is y=0 not b-a=0 also

Answer 11

what are the options u hav?

Answer 12

y=0
y=1
y=2b-2a

Answer 13

ya according to ur question variable is 'y'
so answer will also be of 'y'
but a & b are taken as constants.
& a=b is a condition in which the above eq. become equal.
So choose \[\color{red}{y=0}\]

Answer 14

don't matter about a=b; it is only a condition
but true answer is y=0.
since u have to find the value of "y".

Answer 15

k thanks

Answer 16

yw:)

Answer 17

Good explanation @maheshmeghwal9.

Answer 18

thanx^_^

Answer 19

u r welcome.

Answer 20

:)

Answer 21

:)