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Can you clarify your question a bit? What do you have to do? Simplify it or changing the subjects or ...?
Solve for y using cross multiplication
Cross multiplication:\[\frac{\color{red} a}{\color{blue} b} = \frac{\color{blue} c}{\color{red} d} \text{ implies } \color{red}{ad}=\color{blue}{bc}.\]
\[\frac{y}{p-q} = \frac{y}{p+q}\]\[y(p+q) = y(p-q)\]\[yp+yq = yp-yq\]\[yp+yq-yp + yq = yp-yq - yp + yq\]\[2yq = 0\]\[y=...?\]
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