Question

I will post the question in the reply box...help....

Answer 1

how do i put fraction iin equation editor?this is not the question

Answer 2

\frac{numerator}{denominator} ... in latex
http://www.codecogs.com/latex/eqneditor.php

Answer 3

\[\frac{1}{1+x ^{a-b}+x ^{b-c}} + \frac{1}{1+x ^{b-c}x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}}\]

Answer 4

Prove this

Answer 5

prove that the above is equal to 1

Answer 6

\[ \frac{1}{1+x ^{a-b}+x ^{b-c}} + \frac{1}{1+x ^{b-c} + x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}} \]

Answer 7

yeah prove that that is equal to 1

Answer 8

doesn't look symmetric ... are you sure this is the one?

Answer 9

oh sry it is a-c instead of b-c

Answer 10

\[x^{b-a}=x ^{b}*x ^{-a}=x ^{b}/x ^{a}\]

Answer 11

My supertrick
click right ... show math as => tex commands .... copy the code ... and retype the question

Answer 12

\frac{1}{1+x ^{a-b}+x ^{a-c}} + \frac{1}{1+x ^{b-c} + x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}}

Answer 13

\[\frac{1}{1+x ^{a-b}+x ^{a-c}} + \frac{1}{1+x ^{b-c} + x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}} \]

Answer 14

\[\frac{1}{1+x ^{a-b}+x ^{a-c}} + \frac{1}{1+x ^{b-c} + x ^{b-a}} + \frac{1}{1+x ^{c-b}+x ^{c-a}} =1\]

Answer 15

prove the above thing

Answer 16

multiply
\[ \frac{x^{-a}}{x^{-a}(1+x ^{a-b}+x ^{a-c})}\]
do similar for others

Answer 17

i dont get it hw?

Answer 18

Can u do the same for the others?