Question

9^x-7.3^x+10=0,what is the minimum value wich made this equation correct?given(log2=0.3,log3=0.48)

Answer 1

3^x=u get it!

Answer 2

u²-7.u+10=0

Answer 3

Hmm ... was that 3^x ??not 7.3^x ??

Answer 4

yes my bad

Answer 5

i was wondering it simply was untrue ... lol

Answer 6

3^x=2

Answer 7

x = log 2 / log 3

Answer 8

x=.3/.48

Answer 9

I bet the minimum value that would make this equation true would be
http://www.wolframalpha.com/input/?i=x^2+-+6.3x+%2B+10+%3D+0+

Answer 10

the minimum is 0.625

Answer 11

http://www.wolframalpha.com/input/?i=x^2+-+2+sqrt%2810%29+x+%2B+10+%3D+0+

Answer 12

Hmmm ... is it asking for two values of x??

Answer 13

no only the minimum

Answer 14

Oh ... i guess it is solved as like you did then