Question

How do I evaluate in the real number system, and is this possible? Why or why not? (-9)^1/2

Answer 1

no... because this expression is equivalent to taking the square root of a negative number.

Answer 2

so it's not like:
\[(^{2}\sqrt{-9})\]
\[= ^{2}-\sqrt{9} = -3\]

Answer 3

no... because (-3)(-3) = 9, not -9

Answer 4

ohhh!! okay thank you!

Answer 5

the answer to this comes from the complex numbers.. the real numbers is only a subset of complex numbers...

Answer 6

yw...:)