Ask your own question, for FREE!
Chemistry 23 Online
OpenStudy (anonymous):

HELP!!!!! For the image on the far left, what is the total net force on the object and in which direction? A. 2000 N upwards B. 400 N upwards C. 400 N downwards Image Links: http://curriculum.kcdistancelearning.com/courses/PHYSCIx-FN-A09/a/exams/EM-UnitExam/PSAFDN_Unit5_Exam_77q.jpg

OpenStudy (anonymous):

B

OpenStudy (anonymous):

B. 400 N upwards (1200N-800N)

OpenStudy (anonymous):

With the given fig. ans is B.400N up

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!