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Find the value of X: 4x^2-44=5x
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\(4x^2-5x-44=0\) Send 5x to the other side. Then use the quadratic formula to find the value of x.
Thats what i need help on.. whats the quadratic answer.... ( ) ( )
its 5-5\[(5- or +5\sqrt{11})\div8\]
sorry the second part
no what i got was (4x+11) (x-4) Which would become -16x+11x= -5x So then i got -2.75, 4 as the values of x..
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