Question

81b^2-18b+1 factor

Answer 1

81b^2-18b+1
= (9b)^2 - 2(9b) +1
Using the identity \((a-b)^2 = a^2-2ab+b^2\) to factorise it, you'll get
= (9b-1)^2

Answer 2

ok thank you that was helpful!

Answer 3

Welcome. Hope you understand what I was doing there.