Question

s^3+27

Answer 1

Hint!!!

sum of two cubes is

\[\Large a^3 + b^2 \implies (a+b)(a^2 - ab + b^2)\]

Answer 2

ok thanks for the tip

Answer 3

\[\Huge{s^3+(3)^3}\]
\[\huge{(s+a)(s^2-3s+9)}\]

Answer 4

lol that's supposed to be \[\Large a^3 + b^3\] i think i wrote square