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There are two consecutive odd numbers such that twice the smaller number plus one is ten more than the greater number. What is the smaller number? anyone understand this!?
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2a+1=b-10
Let n, n+2 be two consecutive odd numbers now, we can express the problem as , 2n + 1 = (n+2) + 10
the answer is 1
My answers are 7, 9, 11, & 13
11
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