Question

Plz help:)

Answer 1

If \[x^2+\frac{1}{x^2}=2\]

Answer 2

then find \[x^2+\frac{1}{x^8}\]

Answer 3

=?

Answer 4

how?

Answer 5

nooo

Answer 6

what do u mean question should be wrong?

Answer 7

it's 2 alright.............

Answer 8

hmm not gettting:/

Answer 9

x = 1

Answer 10

solve wat's given

Answer 11

If i make the question whole square ,
can i then solve?

Answer 12

see wat's given.............(x - 1/x)^2 = 0

Answer 13

k! k! i gt it:-)