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Mathematics 16 Online
OpenStudy (maheshmeghwal9):

Plz helP:)

OpenStudy (maheshmeghwal9):

OpenStudy (shubhamsrg):

v=dx/dt = slope of the graph now you just to find the sign of the slope

OpenStudy (btaylor):

at t1, the slope is positive, so v1 is positive, and the slope is increasing around t1, so a1 is positive. at t2, the slope is negative, so v2 is negative, and the slope is decreasing around the point, so a2 is negative. at t3, the slope is negative, so v3 is negative, and the slope is decreasing slowly, so a3 is positive (I believe) v = dx/dt a = d^2x/dt^2

OpenStudy (maheshmeghwal9):

Thanx a lot! @BTaylor

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