Solve using two different methods. Explain which method you found to be efficient. A. 3x-9y= 3 B. 7x-3y= 20 C. y=1/2x-6 6x-3y= -24 5x+3y=16 2x+6y= 19
B elimination method add term by term 7x-3y=20 5x+3y=16 ----------- 12x 0 =36 x=36/12 =3 x=3 hope you can continue it
A. multiplie first equation by -2 and will get -6x+18y=-6 6x-3y=-24 ------------- assum it 0 15y=-30 y=-30/15=-2 y=-2 hope so much that you will can continue it
C. substitute the value of y from the first equation in place of y in second equation good luck bye hope that i was in your help
Thank you for your help it helped me a little bit more
which one would you like to do?
I have to do all three of them...
well I can't show you how to do all three both ways, but I think I have time to walk you through one hopefully that will help you do the others
so pick one...
ok thank you
C
multiply the first equation by 2 what do you get ?
idk i am so confused.........?
sorry, I meant to say 4 y=1/2x-6 2x+6y=19 multiply the first equation by 4 and you get 4y=2x-24 2x+6y=19 now get the first equation arranged so that x and y are on the left side of the equation, and the constant -24 is on the right
Oh okay
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