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The parabola with vertex (2, 3), axis of symmetry parallel to the y-axis, and p = 4.
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\[ (y-y_0)= 4 p (x-x_0)^2 \]
\[ y-3 = 16(x-2)^2\\ y = 3 + 16(x-2)^2\\ y=16 x^2-64 x+67 \]
ok I have the formula but I am get confused on what is x and y and my answer supposed to end in a fraction equation
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