Question

The parabola with vertex (2, 3), axis of symmetry parallel to the y-axis, and p = 4.

Answer 1

\[
(y-y_0)= 4 p (x-x_0)^2
\]

Answer 2

\[
y-3 = 16(x-2)^2\\
y = 3 + 16(x-2)^2\\
y=16 x^2-64 x+67
\]

Answer 3

ok I have the formula but I am get confused on what is x and y and my answer supposed to end in a fraction equation

Answer 4

Did you write the problem correctly?