Question

Solve the following system of equations.
3y = 12
2x + y = -16

Answer 1

3y=12
2x+y=-16
we are gonna use substitution for the y and in order to do that we must isolate the y
2x+y=-16
-2x -2x
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y=-2x-16
Now that we've isolated the y we must substitute y into the top equation.
3(-2x-16)=12 Use the distributive property
-6x-48=12
+48 +48
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-6x= 60
divide negative 6 on both sides
and you get
x=-10<-----
then you substitute x into any of the original equations
so im gonna use the second equation
2(10)+y=-16
20+y=-16
-20 -20
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y= -36<-----