Question

A process equipment contains 100 gallons of water at 25degree Celsius. It is required to bring it to boiling in 10minutes. The heat loss is estimated to be 5%. What is the kW rating of the heater?

Answer 1

1gallon=? liters?

Answer 2

I converted the gallons to cubic meter and multiply it by the density of water to get the mass.

Then I used Q=mc(deltaT) + mLv

Is that right? or only Q=mc(delta T)

Answer 3

only q=mc(deltaT).

Answer 4

why?

Answer 5

and what does it mean by heat loss?

Answer 6

you only need the water to reach the boiling point. You don't want steam

Answer 7

energy required=q+5%q

Answer 8

Thanks @rajathsbhat

Answer 9

i'm assuming you know how to find the power rating...

Answer 10

yes