Question

sin1 sin 3 sin 5 sin 7......sin 89 = 1 / 2 ^ n ..... n = ?

Answer 1

are all those sines multiplied together/

Answer 2

ya

Answer 3

Well.. I don't know if this will help, but the sin 1 = cos 89, so you can rewrite it as:

cos 89 * cos 87 ... * sin 45 * sin 47 * ... * sin 87 * sin 89

simplifying:

1/2 * sin(89 + 89) * 1/2 sin(87 + 87) ... * 1/2sin(47 + 47) * sin(45)

= (1/2)^22 * sin(178) * sin(174) * ... * sin(94) * sin 45

Then try to simplify further.. Maybe the wrong approach, I will think if I get back