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cross product : (-1, 3, 5) and (0, a , 1)
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Evaluate the determinant of \[\begin{bmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k}\\ -1 & 3 &5 \\ 0 &a &1 \end{bmatrix}\]
(3-5a, 1, -a )
i have to solve for 'a', how do i do that ?
Isn't there any other given information?
nope that is it
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Oh yes ! you're right
(12, 1, 12) that's the answer okay i know what to do from here, thank you !
Np.
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