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Mathematics 24 Online
OpenStudy (anonymous):

cross product : (-1, 3, 5) and (0, a , 1)

OpenStudy (blockcolder):

Evaluate the determinant of \[\begin{bmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k}\\ -1 & 3 &5 \\ 0 &a &1 \end{bmatrix}\]

OpenStudy (anonymous):

(3-5a, 1, -a )

OpenStudy (anonymous):

i have to solve for 'a', how do i do that ?

OpenStudy (blockcolder):

Isn't there any other given information?

OpenStudy (anonymous):

nope that is it

OpenStudy (anonymous):

Oh yes ! you're right

OpenStudy (anonymous):

(12, 1, 12) that's the answer okay i know what to do from here, thank you !

OpenStudy (blockcolder):

Np.

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