Question

27a^9b/-9a^2b

Answer 1

\[27a^9b/-9a^2b\]
\[=-3a^7\]

Answer 2

\[\frac{27a^9b}{-9a^2b}\]
\[=\frac{3\times3^2\times a^2\times a^7\times b}{-3^2\times a^2\times b}\]
\[=\frac{3\times\cancel {3^2 }\times \cancel{ a^2}\times a^7\times\cancel b}{-\cancel{3^2}\times \cancel{a^2}\times \cancel{b}}\]

Answer 3

What grade math is this