Plz help:)

Question

Plz help:)

maheshmeghwal9 · Answer

A deer wants to save her life from a lion. The lion follows a path whose equation is $$x^2+y^2=16.$$for saving life, the deer moves on a path whose equation is/are: -

maheshmeghwal9 · Answer

???????????????????

maheshmeghwal9 · Answer

Answer given is: -$$x^2+y^2=4\space  \or \space  x^2+y^2-64=0.$$

anonymous · Answer

so the lion is goin in a circular path of radius 4.......... as long as the deer takes a path with a different radius it is safe.............. do you understand it now? is it a multi-choice question?

maheshmeghwal9 · Answer

but the answer are these 2 only:/

maheshmeghwal9 · Answer

which i have given above.

anonymous · Answer

oh ok so its not a multi-choice ques?

maheshmeghwal9 · Answer

ya it is subjective

asnaseer · Answer

I would go for the larger radius otherwise the lion is continuously surrounding the deer

maheshmeghwal9 · Answer

but the answers are small & big radius both:/

ganeshie8 · Answer

il sleep atthe center..

maheshmeghwal9 · Answer

4 & 64.

maheshmeghwal9 · Answer

?? @ganeshie8

anonymous · Answer

hmm i dont have an explanation as to why dere are two particular solutions, can you scan the question and solution and post it up?

asnaseer · Answer

are you sure you have specified the full question?

maheshmeghwal9 · Answer

ya I have specified full question but if u want solution plz wait for 2 or 3 min.

asnaseer · Answer

if you were the der wouldn't you feel safer running n the larger circle? :)

asnaseer · Answer

*deer

maheshmeghwal9 · Answer

attachment

maheshmeghwal9 · Answer

@asnaseer

asnaseer · Answer

there seems to be some contextual information missing from the question

maheshmeghwal9 · Answer

ya i think too
so what should I do?
Plz guide me:)

maheshmeghwal9 · Answer

I have a same question
may I ask that?

asnaseer · Answer

I can only guide with more information on the question. was there any description relating to this question before the question itself?

maheshmeghwal9 · Answer

no:(
but i have another question same as above.
u plz solve that
I have left doing above question becoz I think that is wrong.

asnaseer · Answer

ok - as long as the new question is not as ambiguous as this one :)

anonymous · Answer

ok post the other question

maheshmeghwal9 · Answer

attachment

maheshmeghwal9 · Answer

the answers are$$(-\sqrt{2},\sqrt{2}).$$

asnaseer · Answer

just substitute x from the first equation into the second and solve for y

anonymous · Answer

so you just have to substitue y=-x

asnaseer · Answer

there should be 2 solutions

maheshmeghwal9 · Answer

wait a minute plz:)

maheshmeghwal9 · Answer

k! but I m getting|dw:1339943982964:dw|