Question

2 log x- 3 log (y+1) write the given expression as a single logarithm

Answer 1

two steps for this one

\[n\log(x)=\log(x^n)\] and
\[\log(x)-\log(y)=\log(\frac{x}{y})\]

Answer 2

use this
\[\log a - \log b = \log a/b\]
\[a \log b = \log b ^{a}\]

Answer 3

how do u work it out?

Answer 4

\[2\log x = \log x ^{2}\]
for example

Answer 5

oops
\[3\log(y+1)=\log((y+1)^3)\]

Answer 6

dont u also get log ^x2/ (y+1)^3

Answer 7

???