Question

How do you factor ones with the power of 6?

Answer 1

\[x ^{6}-y ^{6}\]

Answer 2

difference of two squares or difference of two cubes ;)

Answer 3

\[\Huge{x^6-y^6}\]
\[\Huge{(x^3)^2-(y^3)^2}\]
\[\Huge{(x^3+y^3)(x^3-y^3)}\]
\[\large{[(x+y)(x^2-xy+y^2)][(x-y)(x^2+xy+y^2)]}\]
\[\large{(X^2-y^2)(x^2-xy+y^2)(x^2+xy+y^2)}\]

Answer 4

\[(x^2)^3 - (y^2)^3\]

or

\[(x^3)^2 - (y^3)^2\]

Answer 5

\[\Huge{x^2-y^2=(x+y)(x-y)}\]
\[\Huge{x^3-y^3=(x-y)(x^2+y^2+xy)}\]
\[\Huge{x^3+y^3=(x+y)(x^2+y^2-xy)}\]

Answer 6

these are the three identites that we used here