Question

How do you factor this?

Answer 1

\[h ^{2}-4k ^{2}-4h+4\]

Answer 2

\[\Huge{h^2-4k^2-4h+4}\]
\[\huge{h^2-(2k)^2-4(h-4)}\]
\[\Huge{(h+2k)(h-2k)-4(h-4)}\]

Answer 3

kya baat! @mathslover

Answer 4

or u can do like this \[\Huge{h^2-4h-(2k)^2-(2)^2}\]
\[\Huge{h(h-4)-(2k+2)(2k-2)}\]

Answer 5

Thank you!!

Answer 6

My pleasure @sakigirl