Question

evulate x^2+3y when x=-0.1 and y=-2

Answer 1

what does that mean?

Answer 2

\[x^2+3y\]
when \(x=-0.1\) and \(y=-2\)

\[(-0.1)^2+3(-2)\]\[=-0.1\times-0.1+3\times-2\]

Answer 3

its either -5.99 or 5.99 or 6.1 or -6.01

Answer 4

\[=(−0.1×−0.1)+(3×−2)\]
\[=0.01-6\]

Answer 5

thanks