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Find the vertex of the parabola formed by the following quadratic function: y=x^2-8x+8 a.) (8,8) b.)(-8,136) c.) (4,-8) d.)(-4,56)
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Your function has the form ax^2 + bx + c The x-value of your vertex is given by this formula -b/2a to get the y-value, you can substitute the x-value (-b/2a) for the x in your function, or you can use this formula (4ac - b^2)/4a Hope this helps :)
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