Find the axis of symmetry of the parabola formed by the following quadratic function: y=3x^2+7x-4 a.)x=7/3 b.)x=-7/3 c.)x=7/6 d.)x=-7/6 Please answer!

Question

Find the axis of symmetry of the parabola formed by the following quadratic function: y=3x^2+7x-4   a.)x=7/3   b.)x=-7/3   c.)x=7/6   d.)x=-7/6     Please answer!

shubhamsrg · Answer

i'd be at when the graph attains a maxima or minima (minima in this case)
for that..put y' =0

shubhamsrg · Answer

you may even find roots and find its mean..

anonymous · Answer

Thanks but Id didn't get your answer :/

shubhamsrg · Answer

you know differentiation mam?

anonymous · Answer

Nope

shubhamsrg · Answer

then i guess we should use the second method..
you know quadratic formulla ?

shubhamsrg · Answer

actually,,no need for it really,,can you solve for x ?
3x^2+7x-4 = 0 ?

shubhamsrg · Answer

ohh well,,no need for even that..hmmn
am so sorry..
just tell me this,,what is the sum of roots of 3x^2+7x-4 = 0 ?