Question

Find the axis of symmetry of the parabola formed by the following quadratic function: y=3x^2+7x-4 a.)x=7/3 b.)x=-7/3 c.)x=7/6 d.)x=-7/6 Please answer!

Answer 1

i'd be at when the graph attains a maxima or minima (minima in this case)
for that..put y' =0

Answer 2

you may even find roots and find its mean..

Answer 3

Thanks but Id didn't get your answer :/

Answer 4

you know differentiation mam?

Answer 5

Nope

Answer 6

then i guess we should use the second method..
you know quadratic formulla ?

Answer 7

actually,,no need for it really,,can you solve for x ?
3x^2+7x-4 = 0 ?

Answer 8

ohh well,,no need for even that..hmmn
am so sorry..
just tell me this,,what is the sum of roots of 3x^2+7x-4 = 0 ?