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Find the vertex of the parabola formed by the following quadratic function: y=2x^2=8x+2 a.)(-4,66) b.)(4,2) c.)(-2,26) d.)(2,6)
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using algebra or calculus?
algebra
okay so basically we have formula that comes form the quadratic equation
it says: the x coordinate of the vertex = -b/2a
do you know what the vertex is?
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No, that's the problem
hehe its okay its actually really easy once someone explains it
so basically this part "y=2x^2=8x+2" is a function. If we punch in numbers (x's), it punches out different numbers (y's).
and when we put those numbers on an x y graph it looks like this
correction: y=2x^2+8x+2
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|dw:1340038403307:dw|
this one is a happy face.. its vertex is the point all the way at the bottom
|dw:1340038507050:dw|
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