Find the vertex of the parabola formed by the following quadratic function: y=2x^2=8x+2 a.)(-4,66) b.)(4,2) c.)(-2,26) d.)(2,6)

Question

Find the vertex of the parabola formed by the following quadratic function: y=2x^2=8x+2    a.)(-4,66)   b.)(4,2)   c.)(-2,26)   d.)(2,6)

eyust707 · Answer

using algebra or calculus?

anonymous · Answer

algebra

eyust707 · Answer

okay so basically we have  formula that comes form the quadratic equation

eyust707 · Answer

it says:

the x coordinate of the vertex = -b/2a

eyust707 · Answer

do you know what the vertex is?

anonymous · Answer

No, that's the problem

eyust707 · Answer

hehe its okay its actually really easy once someone explains it

eyust707 · Answer

so basically this part 

"y=2x^2=8x+2"

is a function. If we punch in numbers (x's), it punches out different numbers (y's).

eyust707 · Answer

and when we put those numbers on an x y graph it looks like this

eyust707 · Answer

correction:
y=2x^2+8x+2

eyust707 · Answer

|dw:1340038403307:dw|

eyust707 · Answer

this one is a happy face.. its vertex is the point all the way at the bottom

eyust707 · Answer

|dw:1340038507050:dw|