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(x3 - 18x2 +95x - 126) ÷ (x -9) a. x2 + 9x + 14 b. 9x2 - 9x + 14 c. x2 - 9x + 14 d. x3 -9x2 + 14x + 126
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Two steps: 1. Factor numerator: \[x^3-18 x^2+95 x-126\] \[(x-9) (x-7) (x-2)\] 2. Divide out the (x-9) as if it was just another variable itself \[(x-7) (x-2)\]
F.O.I.L. to get the answer :-) (First, Outer, Inner, Last; add/sum the inner and outer terns to find the middle one)
thanks , but that isnt one of the answer choices :(
just try to solve that one,so that u can have an idea..they already gave u the instruction how to solve that
ive been trying , but its kind of hard , thanks anyways
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